The rate at which popcorn pops was measured at two different temperatures. How many times faster does the popcorn pop at 250°C compared with that at 210°C when the activation energy is 53.8 kJ/mol?

Question

Quizplus · Accepted Answer

The rate of reaction can be compared using the Arrhenius equation. The ratio of rates at two temperatures can be calculated using the formula: (k2/k1) = exp[(Ea/R) * (1/T1 - 1/T2)]. Substituting the given values (Ea = 53.8 kJ/mol, T1 = 210°C = 483K, T2 = 250°C = 523K), the calculation yields approximately 2.8.

The Rate at Which Popcorn Pops Was Measured at Two