Ion interaction energies are determined by Coulomb's law: Determine the energy of potassium chloride if the radius of the potassium ion is 133 pm and that of the chloride ion is 181 pm. A)(-7.36 $\times$ 10^-19 B)(-7.36 $\times$ 10^-22 C)7.36 $\times$10^-19 J D)1.74 $\times$ 10^-18 J E)(-7.36 $\times$10^-25

Question

Quizplus · Accepted Answer

The formula for the interaction energy between two ions is:

E = (k*q1*q2)/r

where:
- k is Coulomb constant (8.99 x 10^9 N m^2 C^-2)
- q1 and q2 are the charges of the ions
- r is the distance between the ions

In this case, we have potassium ion (K+) with charge +1 and chloride ion (Cl-) with charge -1. So:

E = (8.99 * 10^9) * (1 * (-1)) / ((133 + 181) * 10^-12)

= -107.36 x 10^-19 J

= -107.36 J

The negative sign indicates that the ions are attracted to each other. We need to convert the energy to joules.

Therefore, the correct answer is choice A.

Ion Interaction Energies Are Determined by Coulomb's Law: Determine ×\times×

Ion Interaction Energies Are Determined by Coulomb's Law: Determine $\times$