When 1.14 g of octane (molar mass = 114 g/mol) reacts with excess oxygen in a constant volume calorimeter, the temperature of the calorimeter increases by 10.0 $\circ$ C. The heat capacity of the calorimeter is 6.97 kJ/ $\circ$ C. Determine the energy flow, q (reaction).

Question

Quizplus · Accepted Answer

The energy flow, q (reaction), can be determined using the equation q = -CΔT, where C is the heat capacity of the calorimeter and ΔT is the change in temperature. Substituting the given values, we get q = -(6.97 kJ/F1F1F1S1F1F1F10C)(10.0F1F1F1S1F1F1F10C) = -69.7 kJ = (F1F1F1S1F1F1F1069.7 kJ). Therefore, the best choice is C.

When 114 G of Octane (Molar Mass = 114 G/mol) Reacts