Hartmann's solution is used in intravenous therapy to replace lost body fluid and mineral salts. The total ion concentration in Hartmann's solution is 276 mM. It often is prepared from a more concentrated stock solution. How much stock solution is needed to prepare 500 mL of Hartmann's solution? The total ion concentration in the stock solution is 1.38 M.
A)50 mL
B)10 mL
C)100 mL
D)500 mL
E)200 mL

Question

Quizplus · Accepted Answer

To prepare 500 mL of Hartmann's solution with a total ion concentration of 276 mM, we need to calculate the total amount of ions required.

Total ions required = 500 mL x 276 mM = 138 mmol

To find out how much stock solution is needed, we can use the formula:

moles of solute = concentration x volume

Let's assume the volume of stock solution required is x mL. Then,

moles of solute in stock solution = 1.38 M x x mL = 1.38x mmol

We know that the total amount of ions required is 138 mmol. Therefore,

1.38x = 138

x = 100 mL

Therefore, we need 100 mL of the stock solution to prepare 500 mL of Hartmann's solution.

Hartmann's Solution Is Used in Intravenous Therapy to Replace Lost