What is E° of the spontaneous cell made from the Zn²⁺/Zn (-0.76 V) and Br₂/2Br- (1.07 V) half cells?

Question

Quizplus · Accepted Answer

To find the E° of the cell, we need to use the formula: E°cell = E°cathode - E°anode where E°cathode is the standard reduction potential of the cathode half-cell and E°anode is the standard reduction potential of the anode half-cell. From the table of standard reduction potentials, we find that the standard reduction potential of Zn²⁺/Zn is -0.76 V (anode), and the standard reduction potential of Br₂/2Br- is 1.07 V (cathode). Therefore, E°cell = 1.07 V - (-0.76 V) = 1.83 V. The answer is C.

What Is E° of the Spontaneous Cell Made from the Zn2+/Zn

What Is E° of the Spontaneous Cell Made from the Zn²⁺/Zn