Determine Keq at 25°C for the Following Reaction: Pb²⁺(aq)

Determine Keq at 25°C for the following reaction: Pb²⁺(aq) + Cu(s) ⇔ Cu²⁺(aq) + Pb(s)
The half-reactions are:
Pb²⁺(aq) + 2 e- ⇔ Pb(s) E° = -0.125 V
Cu²⁺(aq) + 2 e- ⇔ Cu(s) E° = +0.337 V

A) 2 × 10⁶⁹
B) 2 × 10^-16
C) 2 × 10¹⁶
D) 2 × 10^-8
E) 6 × 10⁷