What is the Ecell for the following concentration cell at 25°C: Pt ∣ H₂(g, 0.025 atm) ∣ H⁺ (0.012 M) || H⁺ (1 M) ∣ H₂ (g, 1 atm) ∣ Pt
2 H⁺(aq) + 2 e- → H₂(g) E° = 0. V

Question

What is the Ecell for the following concentration cell at 25°C: Pt ∣ H₂(g, 0.025 atm) ∣ H⁺ (0.012 M) || H⁺ (1 M) ∣ H₂ (g, 1 atm) ∣ Pt 2 H⁺(aq) + 2 e- → H₂(g) E° = 0. V

Quizplus · Accepted Answer

The Ecell for a concentration cell can be calculated using the Nernst equation: Ecell = E° - (RT/nF) * ln(Q). Since E° = 0 for a concentration cell, Ecell = -(RT/nF) * ln(Q). At 25°C, RT/F = 0.0257 V. For the given cell, n = 2 and Q = (0.012/1) * (1/0.025) = 0.48. Therefore, Ecell = -0.0257/2 * ln(0.48) = +0.066 V.

What Is the Ecell for the Following Concentration Cell at 25°C