Given the following half-reactions occurring in the silver-zinc hearing aid battery, calculate the voltage at 25°C of this battery.
ZnO(s) + H₂O(l) + 2 e- → Zn(s) + 2 OH^- E° = -1.260 V
Ag₂O(s) + H₂O(l) + 2 e- → 2 Ag(s) + 2 OH^- E° = +0.342 V

Question

Quizplus · Accepted Answer

The voltage of the battery is calculated by subtracting the reduction potential of the anode from the reduction potential of the cathode. In this case, the anode is ZnO and the cathode is Ag₂O. Therefore, the voltage of the battery is:E° = E°(cathode) - E°(anode)E° = +0.342 V - (-1.260 V)E° = +1.602 V

Given the Following Half-Reactions Occurring in the Silver-Zinc Hearing Aid