A homeowner in Boston becomes concerned that there may be appreciable amounts of lead in her drinking water due to 150-year old water pipes in her house. Consequently, she takes a sample of her drinking water in to be analyzed. The laboratory technician, who is new on the job, has been told to analyze by precipitating the lead ion as the iodide (Ksp = 7.1 × 10-9 for PbI2) by slowly adding small portions of 1.00 M NaI solution. If we assume that the concentration of lead in the solution is 1.00 mg/liter or approximately 4.8 × 10-6 M (this would be 1.0 part per million) is it possible to detect the lead in the drinking water by adding a total of no more than 10.0 mL of NaI solution to a 100 mL sample of drinking water? You must of course consider dilution effects. What is Q?
A) yes, Q = 4.0 × 10-7
B) yes, Q = 3.6 × 10-8
C) no, Q = 1.6 × 10-13
D) no, Q = 3.6 × 10-8
E) no, Q = 4.0 × 10-7
Correct Answer:
Verified
Q50: If chromium(III) chloride is added to be
Q51: The solubility product constant of Mg(OH)2 is
Q52: When 100 mL each of 2.0 ×
Q53: When 100 mL each of 2.0 ×
Q54: What is the concentration of free Zn2+
Q56: When equal volumes of the indicated solutions
Q57: A solution contains [Ba2+] = 5.0 ×
Q58: To a concentrated buffer of pH 9.0
Q59: In which of the following solutions will
Q60: What is the free Cu2+ concentration if
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents