At a temperature for which the solubility product constant of calcium carbonate is 4.7 × 10^-9, what mass of the salt will dissolve in 100 mL of water?

Question

Quizplus · Accepted Answer

The solubility product constant for calcium carbonate is given by:Ksp = [Ca2+][CO32-] = 4.7 × 10^-9Let x be the molar solubility of calcium carbonate in mol/L. Then, the concentration of calcium ions and carbonate ions in solution will also be x mol/L.Substituting these values into the Ksp expression, we get:4.7 × 10^-9 = x^2Solving for x, we get:x = 2.17 × 10^-5 mol/LThe mass of calcium carbonate that will dissolve in 100 mL of water is:mass = moles × molar massmass = (2.17 × 10^-5 mol/L) × (100.1 g/mol) × (100 mL/1 L)mass = 0.69 mgTherefore, the correct answer is A) 0.69 mg.

At a Temperature for Which the Solubility Product Constant of Calcium