The solubility product constant of PbI2 is 7.1 × 10-9. How many moles of PbI2 will precipitate if 250 ml of a 0.200 M solution of NaI are added to 150 ml of 0.100 M solution of Pb(NO3) 2? You may neglect hydrolysis.
A) 0.050 mol
B) 1.3 × 10-5 mol
C) 0.015 mol
D) 5.6 × 10-3 mol
E) 0.040 mol
Correct Answer:
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