For the reaction: H₂(g) + I₂(g) ⇌ 2 HI(g), Kc = 92.0 When equilibrium concentrations of HI and I₂ are [HI] = 0.115 M and [I₂] = 0.250 M, the equilibrium concentration of [H₂] is:

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is: Kc = [HI]2 / [H₂][I₂] Substituting the given values: 92.0 = (0.115)2 / (x)(0.250) x = 5.75 × 10^-4 M Therefore, the equilibrium concentration of H₂ is 5.75 × 10^-4 M.

For the Reaction: H2(g) + I2(g) ⇌ 2 HI(g), Kc

For the Reaction: H₂(g) + I₂(g) ⇌ 2 HI(g), Kc