For the following chemical equilibrium, Kp = 4.6 × 10^-14 at 25°C, find the value of Kc for this reaction at 25°C. 2 Cl₂(g) + 2 H₂O(g) ⇌ 4 HCl(g) + O₂(g)

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The relationship between Kp and Kc is given by the equation Kp = Kc(RT)^(Δn), where Δn is the change in moles of gas. Here, Δn = 4 + 1 - (2 + 2) = 1. Using R = 0.0821 L·atm/mol·K and T = 298 K, Kc = Kp / (RT) = 4.6 × 10^-14 / (0.0821 × 298) = 1.9 × 10^-15.

For the Following Chemical Equilibrium, Kp = 4