0.75 mol of N₂ and 1.20 mol of H₂ are placed in a 3.0 liter container. When the reaction N₂(g) + 3H₂(g) ⇌ 2 NH₃(g) reaches equilibrium, [H₂] = 0.100 M. Which of the following is true?

Question

Quizplus · Accepted Answer

The initial concentration of H2 is 1.20 mol / 3.0 L = 0.400 M. At equilibrium, [H2] = 0.100 M, so 0.300 M of H2 reacted. Since the reaction consumes 3 moles of H2 for every 2 moles of NH3 produced, [NH3] = (2/3) * 0.300 M = 0.200 M.

075 Mol of N2 and 1

075 Mol of N₂ and 1