For the reaction below CO(g) + 2H₂(g) ⇌ CH₃OH(g)
The equilibrium concentrations at 483 K are [CO(g) ] = 0.0753 M, [H₂(g) ] = 0.151 M, and [CH₃OH(g) ] = 0.0247 M. Calculate the value of Kc.

Question

For the reaction below CO(g) + 2H₂(g) ⇌ CH₃OH(g) The equilibrium concentrations at 483 K are [CO(g)] = 0.0753 M, [H₂(g)] = 0.151 M, and [CH₃OH(g)] = 0.0247 M. Calculate the value of Kc.

Quizplus · Accepted Answer

The equilibrium constant (Kc) for a reaction is calculated using the concentrations of the reactants and products at equilibrium. For the given reaction, the equilibrium constant expression is:Kc = [CH3OH] / ([CO] * [H2]^2)Substituting the given equilibrium concentrations into the expression, we get:Kc = (0.0247 M) / ((0.0753 M) * (0.151 M)^2) = 14.4Therefore, the value of Kc is 14.4.

For the Reaction Below CO(g) + 2H2(g) ⇌ CH3OH(g)

For the Reaction Below CO(g) + 2H₂(g) ⇌ CH₃OH(g)