A 1.38 M solution of nitric acid (63.g/mol)in water (18.0 g/mol)has a density of 1.04 g/mL.What is the mole fraction of nitric acid in the solution?

Question

Quizplus · Accepted Answer

The mole fraction of nitric acid is calculated by dividing the moles of nitric acid by the total moles of the solution. The moles of nitric acid can be calculated by multiplying the molarity by the volume of the solution, and the total moles of the solution can be calculated by multiplying the density by the volume of the solution and dividing by the molar mass of water.Moles of nitric acid = 1.38 M * 1 L = 1.38 molesMoles of water = (1.04 g/mL * 1000 mL/L) / 18.0 g/mol = 57.8 molesTotal moles of solution = 1.38 moles + 57.8 moles = 59.2 molesMole fraction of nitric acid = 1.38 moles / 59.2 moles = 0.0233

A 138 M Solution of Nitric Acid (63