Given the bond enthalpies N-H (389) , Cl-Cl (243) , N-Cl (201) , and H-Cl (431) in kJ/mol, compute ΔH° in kJ/mol for NH3(g) + Cl2(g) → NH2Cl + HCl(g)
A) -393
B) -1100
C) +71
D) +393
E) 0
Correct Answer:
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