H₂S(g) + O₂(g) → H₂O (liq) + SO₂(g) ΔH° = -562.3 kJ 1/8 S₈(s) + O₂(g) → SO(g) ΔH° = -297.0 kJ
H₂(g) + O₂ → H₂O (liq) ΔH° = -266.9 kJ
Compute ΔH° for H₂(g) + 1/8 S8 (s) → H₂S(g) in kJ.

Question

H₂S(g) +

H<sub>2</sub>S(g) + O<sub>2</sub>(g) → H<sub>2</sub>O (liq) + SO<sub>2</sub>(g) ΔH° = -562.3 kJ 1/8 S<sub>8</sub>(s) + O<sub>2</sub>(g) → SO(g) ΔH° = -297.0 kJ H<sub>2</sub>(g) + O<sub>2</sub> → H<sub>2</sub>O (liq) ΔH° = -266.9 kJ Compute ΔH° for H<sub>2</sub>(g) + 1/8 S8 (s) → H<sub>2</sub>S(g) in kJ. A) 562.3 kJ B) 276.6 kJ C) 265.3 kJ D) 20.5 kJ E) -1.6 kJ

O₂(g) → H₂O (liq) + SO₂(g) ΔH° = -562.3 kJ 1/8 S₈(s) + O₂(g) → SO(g) ΔH° = -297.0 kJ
H₂(g) + H2S(g) + O2(g) → H2O (liq) + SO2(g) ΔH° = -562.3 kJ 1/8 S8(s) + O2(g) → SO(g) ΔH° = -297.0 kJ H2(g) + O2 → H2O (liq) ΔH° = -266.9 kJ Compute ΔH° for H2(g) + 1/8 S8 (s) → H2S(g) in kJ. A) 562.3 kJ B) 276.6 kJ C) 265.3 kJ D) 20.5 kJ E) -1.6 kJ

O₂ → H₂O (liq) ΔH° = -266.9 kJ
Compute ΔH° for H₂(g) + 1/8 S8 (s) → H₂S(g) in kJ.

Quizplus · Accepted Answer

The Answer of H₂S(g) + O₂(g) → H₂O (liq) + SO₂(g) ΔH° = -562.3 kJ 1/8 S₈(s) + O₂(g) → SO(g) ΔH° = -297.0 kJ H₂(g) + O₂ → H₂O (liq) ΔH° = -266.9 kJ Compute ΔH° for H₂(g) + 1/8 S8 (s) → H₂S(g) in kJ.

H2S(g) + O2(g) → H2O (Liq) + SO2(g)

H₂S(g) + O₂(g) → H₂O (Liq) + SO₂(g)