Determine the enthalpy change in the following equation:
2/3 H₂S(g) + O₂(g) → 2/3 SO₂(g) + 2/3 H₂O(l)
ΔH°f H₂O(l) = -285.8 kJ/mol
ΔH°f H₂S(g) = -20.63 kJ/mol
ΔH°f SO₂(g) = -296.8 kJ/mol

Question

Quizplus · Accepted Answer

The enthalpy change for the reaction can be calculated using the formula: ΔH° = ΣΔH°f(products) - ΣΔH°f(reactants). For the given reaction, ΔH° = [(2/3 * -296.8) + (2/3 * -285.8)] - [(2/3 * -20.63) + (1 * 0)] = -375 kJ.

Determine the Enthalpy Change in the Following Equation