How much energy is needed to convert 64.6 grams of ice at 0.00°C to water at 55.2°C? Specific heat of ice = 2.10 J/(g°C)
Specific heat of water = 4.18 J/(g°C)
Heat of fusion = 333 J/g
Heat of vaporization = 2258 J/g

Question

Quizplus · Accepted Answer

First, calculate the energy to melt the ice: 64.6 g * 333 J/g = 21,511.8 J. Then, calculate the energy to heat the water from 0°C to 55.2°C: 64.6 g * 4.18 J/(g°C) * 55.2°C = 14,348.6 J. Total energy = 21,511.8 J + 14,348.6 J = 35,860.4 J = 35.9 kJ, which is closest to 36.4 kJ.

How Much Energy Is Needed to Convert 64