A first-order reaction is 54% complete at the end of 12 min. What is the value of the rate constant?

Question

Quizplus · Accepted Answer

The equation for a first-order reaction is ln(No/N) = kt, where No is the initial concentration, N is the concentration at time t, k is the rate constant, and t is time.

If the reaction is 54% complete at the end of 12 minutes, this means that N/No = 0.46. Plugging in these values to the equation and solving for k, we get:

ln(1/0.46) = k(12)
k = ln(1/0.46)/12 = 6.5 x 10^-3 min^-1

Therefore, the answer is C.

A First-Order Reaction Is 54% Complete at the End of 12