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Fe2+ + 2e- → Fe(s) E° = -0

Question 63

Short Answer

Fe2+ + 2e- → Fe(s) E° = -0.440 V
2H+ + 2e- → H2(g) E° = 0.000 V
In a galvanic cell, the iron compartment contains an iron electrode, and [Fe2+] = 1.00 × 10-3 M. The hydrogen compartment contains a platinum electrode (PH2 = 1.00 atm) and a weak acid HA at an initial concentration of 1.00 M. If the observed cell potential is 0.333 V at 25°C, calculate Ka for the weak acid HA at 25°C.

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