Substance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C). For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of:
-ΔG

Question

Quizplus · Accepted Answer

At the normal boiling point of a substance, the liquid and gas phases are in equilibrium at 1 atm pressure. This means that the Gibbs free energy change (ΔG) for the phase transition is zero, because the system is at equilibrium and there is no net change in free energy as the liquid turns into gas.

Substance X Has a Heat of Vaporization of 55