In an isothermal process, the pressure on 1 mol of an ideal monatomic gas suddenly changes from 4.00 atm to 100.0 atm at 25°C.
-Calculate ΔS.

Name: In an isothermal process, the pressure on 1 mol of an ideal monatomic gas suddenly changes from 4.00 atm to 100.0 atm at 25°C. -Calculate ΔS.
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Quizplus · Accepted Answer

In an isothermal process for an ideal gas, ΔS = nRln(Vf/Vi) = nRln(Pi/Pf). For 1 mol of gas, R = 8.314 J/mol·K, Pi = 4.00 atm, Pf = 100.0 atm. ΔS = 1 * 8.314 * ln(4/100) = -26.8 J/K.

In an Isothermal Process, the Pressure on 1 Mol of an Ideal