Substance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C). For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of:
-ΔS

Question

Quizplus · Accepted Answer

The change in entropy (ΔS) for the vaporization process can be calculated using the formula ΔS = ΔH/T, where ΔH is the heat of vaporization and T is the temperature in Kelvin. First, convert 423°C to Kelvin: 423 + 273 = 696 K. Then, calculate ΔS: ΔS = 55.4 kJ/mol / 696 K = 0.0796 kJ/K•mol = 79.6 J/K•mol.

Substance X Has a Heat of Vaporization of 55