One mole of a liquid is vaporized at its boiling point, 65°C and 1.00 atm. ΔHvap for the liquid is 43.8 kJ/mol at 65° C.
-Calculate ΔE.
A) 71.5 kJ
B) 16.1 kJ
C) 41.0 kJ
D) 46.6 kJ
E) none of these
Correct Answer:
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