Using the information below, calculate ΔH°f for PbO(s) .PbO(s) + CO(g) → Pb(s) + CO2(g) , ΔH° = -131.4 kJ
ΔH°f for CO2(g) = -393.5 kJ/mol
ΔH°f for CO(g) = -110.5 kJ/mol
A) +283.0 kJ/mol
B) +252.1 kJ/mol
C) -151.6 kJ/mol
D) -283.0 kJ/mol
E) -372.6 kJ/mol
Correct Answer:
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