Consider the following standard heats of formation:
P₄O₁₀(s) = -3110 kJ/mol
H₂O(l) = -286 kJ/mol
H₃PO₄(s) = -1279 kJ/mol
Calculate the change in enthalpy for the following process:
P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(s)

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The Answer of Consider the following standard heats of formation: P₄O₁₀(s) = -3110 kJ/mol H₂O(l) = -286 kJ/mol H₃PO₄(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process: P₄O₁₀(s) + 6H₂O(l) → 4H₃PO₄(s)

Consider the Following Standard Heats of Formation