Consider the equation 2A(g) 2B(g) + C(g). At a particular temperature, K = 1.6 × 10⁴.If you mixed 5.0 mol B, 0.10 mol C, and 0.0010 mol A in a 1-L container, in which direction would the reaction initially proceed?

Question

Quizplus · Accepted Answer

To determine the direction of the reaction, we need to calculate the reaction quotient Qc and compare it with the equilibrium constant Kc.

Qc = [B]2[C]/[A]2

Substituting the given values, we get:

Qc = (5.0 mol/L)2(0.10 mol/L)/ (0.0010 mol/L)2 = 2.5 x 1011

Since Qc is much larger than Kc (1.6 × 1014), the reaction will proceed in the reverse direction to reach equilibrium. Therefore, the initial direction of the reaction will be to the left.

Consider the Equation 2A(g) 2B(g) + C(g)