For the question(s) that follow, consider the following balanced equation.
Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH) ₂(s) + 2NH₃(g)
-Find the mass of AlCl₃ that is produced when 25.0 grams of Al₂O₃ react with excess HCl according to the following equation.
Al₂O₃(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂O(l)

Question

Quizplus · Accepted Answer

The molar mass of Al₂O₃ is approximately 101.96 g/mol. The molar mass of AlCl₃ is approximately 133.33 g/mol. Using stoichiometry, 25.0 g of Al₂O₃ is equivalent to 0.245 mol. According to the balanced equation, 1 mol of Al₂O₃ produces 2 mol of AlCl₃. Therefore, 0.245 mol of Al₂O₃ will produce 0.49 mol of AlCl₃. The mass of 0.49 mol of AlCl₃ is 0.49 mol × 133.33 g/mol = 65.4 g.

For the Question(s) That Follow, Consider the Following Balanced Equation