Barium chloride and sodium sulfate react according to the following equation.
BaCl₂ + Na 2 SO₄ → BaSO₄ + 2NaCl
Answer the question(s) that follow about this reaction.
-How many grams of barium chloride are needed to make 100. grams of barium sulfate?

Question

Quizplus · Accepted Answer

We need to use stoichiometry to determine the amount of barium chloride needed to make 100 grams of barium sulfate. From the balanced equation, we know that 1 mol of BaCl₂ produces 1 mol of BaSO₄. The molar mass of BaSO₄ is 233.4 g/mol.

First, we need to find the number of moles of BaSO₄ produced from 100 grams:

100 g BaSO₄ x (1 mol / 233.4 g) = 0.428 mol BaSO₄

Since 1 mol of BaCl₂ produces 1 mol of BaSO₄, we need 0.428 moles of BaCl₂. The molar mass of BaCl₂ is 208.23 g/mol.

0.428 mol BaCl₂ x (208.23 g / mol) = 89.3 g BaCl₂

Therefore, we need 89.3 grams of barium chloride to make 100 grams of barium sulfate.

Barium Chloride and Sodium Sulfate React According to the Following