How many mL of 0.246 M Pb(NO₃)₂ are needed to react with 36.0 mL of 0.322 M KCl ? 2KCl(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbCl₂(s) A)36.0 mL B)18.0 mL C)72.0 mL D)47.1 mL E)23.6 mL

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The balanced equation shows a 1:2 molar ratio between Pb(NO₃)₂ and KCl. Calculate moles of KCl, then use the ratio to find moles of Pb(NO₃)₂ needed, and finally convert to volume using its molarity.

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