An inductance L, resistance R, and ideal battery of emf are wired in series. A switch in the circuit is closed at time 0, at which time the current is zero. At any later time t the potential difference across the resistor is given by: A) $\varepsilon$(1 - e^-^Lt^/^R) B) $\varepsilon$e^-^Lt^/^R C) $\varepsilon$(1 + e^-^Rt^/^L) D) $\varepsilon$e^-^Rt^/^L E) $\varepsilon$(1 - e^-^Rt^/^L)

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The Answer of An inductance L, resistance R, and ideal battery of emf are wired in series. A switch in the circuit is closed at time 0, at which time the current is zero. At any later time t the potential difference across the resistor is given by: A) $\varepsilon$(1 - e^-^Lt^/^R) B) $\varepsilon$e^-^Lt^/^R C) $\varepsilon$(1 + e^-^Rt^/^L) D) $\varepsilon$e^-^Rt^/^L E) $\varepsilon$(1 - e^-^Rt^/^L)

An Inductance L, Resistance R, and Ideal Battery of Emf ε\varepsilonε

An Inductance L, Resistance R, and Ideal Battery of Emf $\varepsilon$