An 8.0-mH inductor and a 2.0-$\Omega$ resistor are wired in series to a 20-V ideal battery. A switch in the circuit is closed at time 0, at which time the current is zero. After a long time the current in the resistor and the current in the inductor are:
A) 0, 0
B) 10 A, 10 A
C) 2.5 A, 2.5 A
D) 10 A, 2.5 A
E) 10 A, 0

Question

Quizplus · Accepted Answer

After a long time, the inductor behaves like a short circuit, so the current is determined by Ohm's law: I = V/R = 20V/2Ω = 10 A.

An 80-MH Inductor and a 2 Ω\OmegaΩ Resistor Are Wired in Series to a 20-V Ideal Battery

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