A total resistance of 3.0 $\Omega$ is to be produced by combining an unknown resistor R with a 12 $\Omega$ resistor. What is the value of R and how is it to be connected to the 12 $\Omega$ resistor?
A) 4.0 $\Omega$, parallel
B) 4.0 $\Omega$, series
C) 2.4 $\Omega$, parallel
D) 2.4 $\Omega$, series
E) 9.0 $\Omega$, series

Question

A total resistance of 3.0  $\Omega$ is to be produced by combining an unknown resistor R with a 12 $\Omega$ resistor. What is the value of R and how is it to be connected to the 12  $\Omega$ resistor?
A) 4.0  $\Omega$, parallel
B) 4.0  $\Omega$, series
C) 2.4  $\Omega$, parallel
D) 2.4  $\Omega$, series
E) 9.0  $\Omega$, series

Quizplus · Accepted Answer

The total resistance of two resistors in parallel is given by:1/R_total = 1/R1 + 1/R2Substituting the given values, we get:1/3 = 1/12 + 1/RSolving for R, we get:R = 4 ohmsTherefore, the unknown resistor R should be connected in parallel with the 12 ohm resistor to produce a total resistance of 3 ohms.

A Total Resistance of 3 Ω\OmegaΩ Is to Be Produced by Combining an Unknown Resistor R

A Total Resistance of 3 $\Omega$ Is to Be Produced by Combining an Unknown Resistor R