In an antique automobile, a 6-V battery supplies a total of 48 W to two identical headlights in parallel. The resistance (in ohms) of each bulb is:
A) 0.67
B) 1.5
C) 3
D) 4
E) 8

Question

Quizplus · Accepted Answer

We can use the formula P = V^2/R to solve this problem, where P is the power in watts, V is the voltage in volts, and R is the resistance in ohms.

Since the battery supplies a total of 48 W to two identical headlights in parallel, each headlight receives 24 W.

Also, since the battery has a voltage of 6 V, each headlight has a voltage of 6 V.

So we can plug in P = 24 W and V = 6 V into the formula and solve for R:

24 = 6^2/R

24R = 6^2

R = 6^2/24 = 1.5

Therefore, the resistance of each bulb is 1.5 ohms.

In an Antique Automobile, a 6-V Battery Supplies a Total