A conducting sphere has charge Q and its electric potential is V, relative to the potential far away.If the charge is doubled to 2Q, the potential is:

Question

Quizplus · Accepted Answer

The electric potential of a conducting sphere depends only on the charge and the radius of the sphere. It is given by V = kQ/r, where k is Coulomb's constant and r is the radius of the sphere. Since the distance from the sphere to the reference point far away is constant, r does not change. Thus, when the charge is doubled to 2Q, the potential becomes V = k(2Q)/r = 2(kQ/r) = 2V. Therefore, the correct answer is B.

A Conducting Sphere Has Charge Q and Its Electric Potential