The dissolving of sodium acetate (NaC₂H₃O₂ = 82.04 g/mol) in water can be described by the following reaction: NaC₂H₃O₂ (s) $\rightarrow$ NaC₂H₃O₂ (aq) $\Delta$ H = -17.2 kJ
How much heat will be released when 125 g of sodium acetate dissolve in water?

Question

The dissolving of sodium acetate (NaC₂H₃O₂ = 82.04 g/mol) in water can be described by the following reaction: NaC₂H₃O₂ (s)

\rightarrow

NaC₂H₃O₂ (aq)

\Delta

H = -17.2 kJ
How much heat will be released when 125 g of sodium acetate dissolve in water?

Quizplus · Accepted Answer

The heat released can be calculated using the molar heat of solution. First, find the number of moles of sodium acetate: $ \frac{125 \, \text{g}}{82.04 \, \text{g/mol}} = 1.523 \, \text{moles} $. Then, multiply the number of moles by the heat of solution per mole: $ 1.523 \, \text{moles} \times -17.2 \, \text{kJ/mol} = -26.2 \, \text{kJ} $.

The Dissolving of Sodium Acetate (NaC2H3O2 = 82 →\rightarrow→ NaC2H3O2 (Aq) Δ\DeltaΔ

The Dissolving of Sodium Acetate (NaC₂H₃O₂ = 82 $\rightarrow$ NaC₂H₃O₂ (Aq) $\Delta$