The dissolving of ammonium nitrate (NH₄NO₃ = 80.06 g/mol) in water can be described by the following reaction: NH₄NO₃ (s) $\rightarrow$ NH₄NO₃ (aq) $\Delta$ H = +25.4 kJ
How much heat will be absorbed when 175 g of sodium acetate dissolve in water?

Question

The dissolving of ammonium nitrate (NH₄NO₃ = 80.06 g/mol) in water can be described by the following reaction: NH₄NO₃ (s)

\rightarrow

NH₄NO₃ (aq)

\Delta

H = +25.4 kJ
How much heat will be absorbed when 175 g of sodium acetate dissolve in water?

Quizplus · Accepted Answer

The heat absorbed can be calculated using the given enthalpy change and the mass of the substance. Given that the enthalpy change for dissolving ammonium nitrate is +25.4 kJ per mole, and the molar mass is 80.06 g/mol, for 175 g of the substance, the calculation is as follows: (175 g / 80.06 g/mol) * 25.4 kJ/mol = 55.5 kJ.

The Dissolving of Ammonium Nitrate (NH4NO3 = 80 →\rightarrow→ NH4NO3 (Aq) Δ\DeltaΔ

The Dissolving of Ammonium Nitrate (NH₄NO₃ = 80 $\rightarrow$ NH₄NO₃ (Aq) $\Delta$