A chemist carries out this reaction in the laboratory using 4.31 grams of zinc and an excess of sulfur: Zn + S $\rightarrow$ ZnS
From the balanced equation,she calculates that she should obtain 6.41 grams of zinc sulfide.However,she isolates only 5.85 grams of product.What is her percent yield for this reaction?

Question

Quizplus · Accepted Answer

Theoretical yield of ZnS = 6.41 g

Actual yield of ZnS = 5.85 g

%Hence, percent yield = (actual yield/theoretical yield) × 100

percent yield = (5.85 g/6.41 g) × 100

percent yield = 91.3%

Therefore, the answer is D (91.3%).

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