Consider the following reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃
How many grams of oxygen gas are needed to react completely with 44.2 grams of iron?

Question

Consider the following reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃ How many grams of oxygen gas are needed to react completely with 44.2 grams of iron?

Quizplus · Accepted Answer

First, we need to correct the reaction formula, which seems to be a formatting error. The correct reaction is likely: $4 \text{Fe} + 3 \text{O}_2 \rightarrow 2 \text{Fe}_2\text{O}_3$. To find out how many grams of $\text{O}_2$ are needed to react with 44.2 grams of iron, we use the molar mass of iron ($55.85 \text{g/mol}$) to find moles of iron, then use the stoichiometry of the reaction to find moles of $\text{O}_2$ needed, and finally convert those moles to grams using the molar mass of $\text{O}_2$ ($32 \text{g/mol}$).$$\text{Moles of Fe} = \frac{44.2 \text{g}}{55.85 \text{g/mol}} \approx 0.791 \text{mol}$$From the balanced equation, $4 \text{mol}$ of Fe react with $3 \text{mol}$ of $\text{O}_2$, so:$$\text{Moles of } \text{O}_2 = \frac{3}{4} \times 0.791 \text{mol} \approx 0.593 \text{mol}$$Converting moles of $\text{O}_2$ to grams:$$\text{Grams of } \text{O}_2 = 0.593 \text{mol} \times 32 \text{g/mol} \approx 19.0 \text{g}$$Therefore, 19.0 grams of oxygen gas are needed to react completely with 44.2 grams of iron.

Consider the Following Reaction: 4 Fe + 3 O2 →\rightarrow→ 2 Fe2O3 How Many Grams of Oxygen Gas Are Needed

Consider the Following Reaction: 4 Fe + 3 O₂ $\rightarrow$ 2 Fe₂O₃
How Many Grams of Oxygen Gas Are Needed