In a saturated solution of cobalt(II)carbonate,CoCO₃,both [Co²⁺] and [CO₃²^-] = 3.7 × 10^-⁷ M.Calculate the value of the solubility product for this compound.

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The solubility product (Ksp) for a compound is the product of the molar concentrations of the ions in a saturated solution, each raised to the power of its stoichiometric coefficient in the balanced chemical equation. For CoCO3, the balanced chemical equation for the dissolution reaction is:CoCO3(s) <=> Co2+(aq) + CO32-(aq)The Ksp expression for CoCO3 is:Ksp = [Co2+][CO32-]Substituting the given concentrations into the Ksp expression, we get:Ksp = (3.7 × 10^-7 M)(3.7 × 10^-7 M) = 1.4 × 10^-13 M^2Therefore, the solubility product for CoCO3 is 1.4 × 10^-13 M^2.

In a Saturated Solution of Cobalt(II)carbonate,CoCO3,both [Co2+] and [CO32-] =

In a Saturated Solution of Cobalt(II)carbonate,CoCO₃,both [Co²⁺] and [CO₃²^-] =