What is the oxidation number of chromium in Cr₂O₇²^-?

Question

Quizplus · Accepted Answer

In this compound, sulfur has an oxidation state of -2, oxygen has an oxidation state of -2, and hydrogen has an oxidation state of +1. The overall compound has a total charge of -1. To find the oxidation state of chromium, we can set up the following equation:
x + (-2) + 12(-2) + (-1) = -1
where x is the oxidation state of chromium. Solving for x gives us x = +6. Therefore, the oxidation number of chromium in this compound is +6.

What Is the Oxidation Number of Chromium in Cr2O72-

What Is the Oxidation Number of Chromium in Cr₂O₇²^-