Calculate the normality of a potassium hydroxide solution if 27.7 mL of the solution is needed to neutralize 0.477 g of sulfamic acid in the reaction NH₂SO₃H + KOH $\rightarrow$NH₂SO₃K + H₂O.

Question

Quizplus · Accepted Answer

Normality is calculated by dividing the equivalents of solute by the volume of solution in liters. The equivalent weight of sulfamic acid is its molar mass (97.09 g/mol) divided by 1 (since it donates one proton). The equivalents of sulfamic acid are 0.477 g / 97.09 g/mol = 0.00492 equivalents. The volume of KOH solution is 27.7 mL = 0.0277 L. Normality = 0.00492 equivalents / 0.0277 L = 0.177 N.

Calculate the Normality of a Potassium Hydroxide Solution If 27 →\rightarrow→

Calculate the Normality of a Potassium Hydroxide Solution If 27 $\rightarrow$