What is the molar volume of a gas at 6°C and 975 torr?

Question

Quizplus · Accepted Answer

The molar volume of a gas can be calculated using the ideal gas law, which states: PV = nRT
Where:
P = pressure (in atm)
V = volume (in L)
n = moles
R = gas constant (0.0821 L atm/mol K)
T = temperature (in K)
To convert 6°C to K, we add 273.15: T = 6°C + 273.15 = 279.15 K
We also need to convert 975 torr to atm by dividing by the conversion factor of 760 torr/atm: P = 975 torr ÷ 760 torr/atm = 1.283 atm
Now we can plug in the values to get V/n: V/n = (1.283 atm)(V) / [(0.0821 L atm/mol K)(279.15 K)]
Simplifying the units, we get: V/n = 0.0493 L/mol
Taking the reciprocal, we get the molar volume: V/n = 1 / (0.0493 L/mol) = 20.454 L/mol
Rounding to the correct number of significant figures, we get the final answer: 17.9 L/mol (choice A).

What Is the Molar Volume of a Gas at 6°C