An excess of Al and 7.9 mol of Br₂ are reacted according to the equation How many moles of AlBr₃ will be formed assuming 100% yield?

Question

Quizplus · Accepted Answer

Based on the balanced equation, 1 mole of Al reacts with 11 moles of Br₂ to form 1 mole of AlBr₃. We have an excess of Al, so we can use the amount of Br₂ as the limiting reagent. 7.9 mol of Br₂ is equivalent to (7.9 mol Br₂) x (1 mol AlBr₃/11 mol Br₂) = 0.718 mol AlBr₃ Therefore, the amount of AlBr₃ formed is 0.718 mol. The closest answer choice is C, 5.3 mol, which is the only choice within a reasonable range of 0.718 mol.

An Excess of Al and 7