A cylinder is 0.10 m in radius and 0.20 m in length.Its rotational inertia, about the cylinder axis on which it is mounted, is 0.020 kg . m².A string is wound around the cylinder and pulled with a force of 1.0 N.The angular acceleration of the cylinder is: A)2.5 rad/s² B)5.0 rad/s² C)10 rad/s² D)15 rad/s² E)20 rad/s²

Question

Quizplus · Accepted Answer

The torque exerted on the cylinder is given by:
τ = RF = (0.10 m)(1.0 N) = 0.10 Nm
Using the formula for rotational acceleration:
α = τ/I
where I is the rotational inertia, we get:
α = (0.10 Nm)/(0.020 kg m^2) = 5.0 rad/s^2
Therefore, the angular acceleration of the cylinder is 5.0 rad/s^2, which is choice (B).

A Cylinder Is 0