A disk with a rotational inertia of 5.0 kg∙m² and a radius of 0.25 m rotates on a fixed axis perpendicular to the disk and through its center.A force of 2.0 N is applied tangentially to the rim.As the disk turns through half a revolution the work done by the force is: A)1.6 J B)2.5 J C)6.3 J D)10 J E)40 J

Question

Quizplus · Accepted Answer

Work done = Force × distance = 2 N × (π × 0.25 m) = 1.6 J

A Disk with a Rotational Inertia of 5