Fifty grams of ice at 0 ° C is placed in a thermos bottle containing one hundred grams of water at 6 ° C.How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the specific heat of water is 4190 J/kg K.

Question

Fifty grams of ice at 0 ° C is placed in a thermos bottle containing one hundred grams of water at 6 °  C.How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the specific heat of water is 4190 J/kg  K.

Quizplus · Accepted Answer

The heat required to melt the ice is equal to the heat released by the water as it cools down to 0°C. The heat required to melt the ice is given by:Q = mLwhere m is the mass of the ice and L is the heat of fusion of water.The heat released by the water as it cools down to 0°C is given by:Q = mcΔTwhere m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.Setting these two equations equal to each other, we get:mL = mcΔTSolving for m, we get:m = (mcΔT)/LSubstituting in the given values, we get:m = (100 g x 4190 J/kg K x (6°C - 0°C))/(333 kJ/kg)= 7.5 gTherefore, 7.5 g of ice will melt.

Fifty Grams of Ice at 0 ° C Is Placed