Assume that helium behaves as an ideal monatomic gas.If 2 moles of helium undergo a temperature increase of 100 K at constant volume, how much work is done by the gas?
A)0 J
B)1700 J
C)2500 J
D)4200 J
E)5000 J

Question

Quizplus · Accepted Answer

As the gas undergoes a temperature increase at constant volume, no work is done by the gas. The formula for the work done by a gas is  W = nRT ln(V₂/V₁), where V₂ is the final volume, V₁ is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the temperature change. Since the volume is constant in this case, V₂/V₁ = 1 and ln(1) = 0. Therefore, the work done by the gas is 0 J.

Assume That Helium Behaves as an Ideal Monatomic Gas